Esta pregunta es una extensión de esta publicación
Quiero unir cuatro tablas diferentes con SQLite que tienen solo dos columnas en común. Sin embargo, suponga que hay más de 30 columnas, es decir, más que las columnas a – h . Por favor, eche un vistazo al siguiente ejemplo
Tabla 1:
ab lon lat --------------- 22 33 11 22
Tabla 2:
cd lon lat --------------- 1 2 44 45
Tabla 3
ef lon lat ----------------------- NULL NULL 100 101
Table4
gh lon lat ----------------------- NULL NULL 200 201
La solución actual es la siguiente
SELECT a,b,NULL AS c, NULL AS d,NULL AS e, NULL AS f, NULL AS g, NULL AS h, lon,lat FROM table1 UNION ALL SELECT NULL, NULL,c,d,NULL AS e, NULL AS f, NULL AS g, NULL AS h, lon,lat FROM table2 UNION ALL SELECT NULL, NULL,NULL,NULL,e,f, NULL AS g, NULL AS h, lon,lat FROM table3 UNION ALL SELECT NULL, NULL,NULL,NULL,NULL,NULL,g,h, lon,lat from table4
Resultado:
+------+------+------+------+------+------+------+------+-----+-----+ | a | b | c | d | e | f | g | h | lon | lat | +------+------+------+------+------+------+------+------+-----+-----+ | 22 | 33 | NULL | NULL | NULL | NULL | NULL | NULL | 11 | 22 | | NULL | NULL | 1 | 2 | NULL | NULL | NULL | NULL | 44 | 45 | | NULL | NULL | NULL | NULL | NULL | NULL | NULL | NULL | 100 | 101 | | NULL | NULL | NULL | NULL | NULL | NULL | NULL | NULL | 200 | 201 | +------+------+------+------+------+------+------+------+-----+-----+
MANIFESTACIÓN
No creo que haya una manera particularmente buena de hacerlo cuando tienes más de 30 columnas. Lo siguiente es lo mejor que puedo hacer, usando CTE nesteds para implementar uniones exteriores completas , y luego uso coalesce
para elegir el primer Lat / Lon no nulo.
Todavía se requiere enumerar los más de 30 campos en la statement SELECT
superior, pero al less las lists masivas de NULL AS ...
no son necesarias:
SELECT a, b, c, d, e, f, g, h, coalesce(lat1, lat2, lat3, lat4) AS lat, coalesce(lon1, lon2, lon3, lon4) AS lon FROM ( WITH t1_x_t2 AS ( SELECT t1.*, t2.*, t1.lat AS lat1, t2.lat AS lat2, t1.lon AS lon1, t2.lon AS lon2 FROM table1 t1 LEFT OUTER JOIN table2 t2 ON 0 UNION ALL SELECT t1.*, t2.*, t1.lat AS lat1, t2.lat AS lat2, t1.lon AS lon1, t2.lon AS lon2 FROM table2 t2 LEFT OUTER JOIN table1 t1 ON 0 ), t3_x_t4 AS ( SELECT t3.*, t4.*, t3.lat AS lat3, t4.lat AS lat4, t3.lon AS lon3, t4.lon AS lon4 FROM table3 t3 LEFT OUTER JOIN table4 t4 ON 0 UNION ALL SELECT t3.*, t4.*, t3.lat AS lat3, t4.lat AS lat4, t3.lon AS lon3, t4.lon AS lon4 FROM table4 t4 LEFT OUTER JOIN table3 t3 ON 0 ) SELECT t1_x_t2.*, t3_x_t4.* FROM t1_x_t2 LEFT OUTER JOIN t3_x_t4 ON 0 UNION ALL SELECT t1_x_t2.*, t3_x_t4.* FROM t3_x_t4 LEFT OUTER JOIN t1_x_t2 ON 0 )
Una forma de derivar el resultado usando pivot()
(si su dbms
admite) podría ser el siguiente.
select a,b,c,d,e,f,g,h,lon,lat from ( select 'a' as columnName1, a as val1,'b' as ColumnName2, b as val2, lon,lat from table1 union all select 'c',c,'d', d, lon,lat from table2 union all select 'e',e,'f', f, lon,lat from table3 union all select 'g',g,'h', h, lon,lat from table4 ) t1 PIVOT (MAX(val1) FOR columnName1 IN (a,c,e,g)) as Pivot1 PIVOT (MAX(val2) FOR columnName2 IN (b,d,f,h)) AS Pivot2;
Resultado:
+------+------+------+------+------+------+------+------+-----+-----+ | a | b | c | d | e | f | g | h | lon | lat | +------+------+------+------+------+------+------+------+-----+-----+ | 22 | 33 | NULL | NULL | NULL | NULL | NULL | NULL | 11 | 22 | | NULL | NULL | 1 | 2 | NULL | NULL | NULL | NULL | 44 | 45 | | NULL | NULL | NULL | NULL | NULL | NULL | NULL | NULL | 100 | 101 | | NULL | NULL | NULL | NULL | NULL | NULL | NULL | NULL | 200 | 201 | +------+------+------+------+------+------+------+------+-----+-----+
MANIFESTACIÓN
PD: Tenga en count que la consulta anterior es para sql-Server
, por lo que probablemente necesite cambiarla por su dbms
.